Open Radar

 
Summary:
When I define a function parameter as inout, I use the "inout" keyword.

When I pass an argument into an inout parameter, I use the sigil "&". But nothing about an ampersand suggests "inout". It feels like a misplaced C vestige.

I suggest that after defining a function with an inout parameter, like so:

  func swap(inout a:Int, inout b:Int) -> () { // ... }

the most logical syntax for the functional call is like so:

  swap(inout a, inout b)

Steps to Reproduce:
1. Define a function with an inout parameter
2. Call the function

Expected Results:
Use a logical syntax for function call

Actual Results:
Use a vestigial C syntax for the function call

Version:


Notes:


Configuration:
Xcode6-Beta

Attachments: