Swift: Define type aliases among type constraints
| Originator: | rix.rob | ||
| Number: | rdar://17893483 | Date Originated: | 02-Aug-2014 12:06 AM |
| Status: | Open | Resolved: | |
| Product: | Developer Tools | Product Version: | Xcode6-Beta4 (6A267n) |
| Classification: | Enhancement | Reproducible: | Not Applicable |
Summary:
It would be extremely convenient to be able to define type aliases in the type parameters/constraints list.
For example, I’m implementing a polynomial algebra and I have the following definition for multiplication:
func * <Constant : Ring, Variable> (x: Term<Constant, Variable>, y: Term<Constant, Variable>) -> Term<Constant, Variable> {
return Term(multiplication: x, y)
}
I’m having to repeat Term<Constant, Variable> quite a lot. It would be really nice to be able to define an alias:
func * <Constant : Ring, Variable, typealias Expression = Term<Constant, Variable>> (x: Expression, y: Expression) -> Expression {
return Term(multiplication: x, y)
}
An alternative syntax would be to allow = to define an alias in a constraint:
func * <Constant : Ring, Variable, Expression where Expression = Term<Constant, Variable>> (x: Expression, y: Expression) -> Expression
Or just use ==, and make non-generic type constraints define typealiases instead of throwing errors.
Steps to Reproduce:
N/A
Expected Results:
N/A
Actual Results:
N/A
Regression:
N/A
Notes:
N/A
Comments
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