Swift: Overload function call syntax
| Originator: | rix.rob | ||
| Number: | rdar://18141648 | Date Originated: | 26-Aug-2014 07:47 PM |
| Status: | Open | Resolved: | |
| Product: | Developer Tools | Product Version: | Xcode6-Beta6 (6A280e) |
| Classification: | Enhancement | Reproducible: | Always |
Summary:
It’s often convenient to wrap functions in a structure of some description which operates like the function while maintaining some state or associated behaviour.
Actually calling the wrapped behaviour would be much more convenient if function call syntax were overloadable similarly to read-only subscripting or operator overloading:
struct F<T, U> {
let f: T -> U
call(x: T) -> U { // subscript–style syntax
return f(x)
}
}
postfix func ()<T, U> (f: F<T, U>, x: T) -> U { // operator–style syntax
return f.f(x)
}
One can already define a method named `call` or similar, but it’s rather noisier syntactically.
Steps to Reproduce:
N/A
Expected Results:
N/A
Actual Results:
N/A
Regression:
N/A
Notes:
N/A
Comments
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