Open Radar

 
Summary:
Say we have a function with a variadic argument of enum type. If we pass in only one argument, the enum must be fully qualified. If we pass in more than one argument, the enums don't have to be fully qualified.

The compiler should not treat a single T passed into a function with a T... vararg parameter as a [T], which seems to be the cause of this error.

An annotated sample project demonstrating this has been enclosed.

Steps to Reproduce:
1. Define an enum:
enum MyEnum { case Foo, Bar, Baz }

2. Define a function taking a variadic parameter of that enum type:
func variadicFunc(x: MyEnum...) { /* do stuff */ }

3. Try to call the function with the non-fully-qualified enum:
variadicFunc(.Foo)

Expected Results:
This code should compile, and act identically as "variadicFunc(MyEnum..Foo)", which does compile and work as expected.

Actual Results:
The code does not compile, with the error "'(MyEnum...).Type" does not have a member named 'Foo'"

Version:
Xcode 6.1.1 (6A2008a), OS X 10.9.5