Swift: Using a variable of type int should be possible to use in a `if`
| Originator: | romaaan.git | ||
| Number: | rdar://22075800 | Date Originated: | 2015-08-03 |
| Status: | Open | Resolved: | |
| Product: | Developer Tools | Product Version: | |
| Classification: | Reproducible: | Always |
Summary:
Objective-C and other languages resolve an int greater than zero to `true` and values equal or lower than zero to `false`. Using the attached sample code leads to the error message:
Type `int` does not conform to protocol `BooleanType`
Steps to Reproduce:
if 1 {
println("True")
} else {
println("False")
}
Expected Results:
The if structure should print "True"
Actual Results:
Error message: Type `int` does not conform to protocol `BooleanType`
Version:
Xcode 6.4 / Swift 1.2 iOS 8
Comments
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From The Swift Programming Language:
"Swift’s type safety prevents non-Boolean values from being substituted for Bool. The following example reports a compile-time error:
let i = 1
if i {
// this example will not compile, and will report an error
} "
This behavior is intentional, and will likely not be changed.
It is, however, relatively simple to extend Int to make it conform to BooleanType, but it's not advisable.